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WIFOM (Game): Difference between revisions

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If we ignore all combinations that result in 0 points, there are 13 combinations. Of those 13, four of them are effectively duplicates (such as NAA and NPP), leaving us with a total number of 9 unique combinations.<br /><br />
Four of those nine combinations are won by not drinking anything (those of which the drinker is not poisoned will always be won by not drinking). Four of those nine can be won by drinking Glass A. Four of those nine can be won by drinking Glass B. Three can be won by drinking both glasses.

Revision as of 21:01, 1 May 2013

WIFOM (Game) is a game developed by Who and Zaicon via the MafiaScum Site Chat.

The standard version of this game is 2-player, although a 3-player version of this game is playable.

The Setup

One player will pour the wine; the other player will be the drinker. Turns alternate after every round.

The pourer must first choose whether to poison the drinker or not. Then, the pourer can place either an antidote, some poison, or nothing in each glass (all combinations are allowed, one per glass).

After that, the game can begin. If there is a mod, the pourer should notify the mod of his/her choices at this point.

The Play

Typically, the drinker will ask questions to help determine what to drink (if anything). The drinker can choose to drink from neither glass, one glass (the drinker must specify whose glass to drink from), or both glasses.

The drinker wins if he/she is still alive. One dose of antidote will cancel out one dose of poison (being poisoned to start with counts as one dose of poison). However, the antidote by itself is also harmful and will kill the drinker if there is no poison to cancel it out.

Scoring

If the drinker lives, the drinker gets points equal to the number of wrong choices there were. If the drinker dies, the pourer gets points equal to the number of right choices there were.

Right/wrong choices refer to the different options available to the pourer (drink from no glasses, drink from glass A, drink from glass B, and drink from both glasses). A "right" choice is a choice that allows the drinker to live.

Example

Let's say Player A is the pourer and Player B is the drinker.

Privately, Player A decides to poison Player B and put a dose of antidote into each glass. Once the decision has been made, Player B can start asking questions of the pourer. Eventually, Player B decides to drink from both glasses.

Since Player B has a dose of poison and two doses of antidote in his/her system, he/she dies (one of the antidotes does not cancel out). Player A gets a total of two points because there were two options available to Player B that would have allowed him/her to live (by drinking either glass, but not both).

Theory

There are a total of 18 possible combinations for the poison and antidotes (including whether or not the drinker is poisoned). They are listed below.

Letter Code Drinker Glass A Glass B Points for Drinker Points for Pourer How to win
NAA Not poisoned Antidote Antidote 3 1 Drink 0
NAN Not poisoned Antidote Nothing 2 2 Drink 0 / Drink B
NAP Not poisoned Antidote Poison 2 2 Drink 0 / Drink 2
NNA Not poisoned Nothing Antidote 2 2 Drink 0 / Drink A
NNN Not poisoned Nothing Nothing 0 N/A Drink 0 / Drink A / Drink B / Drink A & B
NNP Not poisoned Nothing Poison 2 2 Drink 0 / Drink A
NPA Not poisoned Poison Antidote 2 2 Drink 0 / Drink 2
NPN Not poisoned Poison Nothing 2 2 Drink 0 / Drink B
NPP Not poisoned Poison Poison 3 1 Drink 0
PAA Poisoned Antidote Antidote 2 2 Drink A / Drink B
PAN Poisoned Antidote Nothing 2 2 Drink A / Drink 2
PAP Poisoned Antidote Poison 3 1 Drink A
PNA Poisoned Nothing Antidote 2 2 Drink B / Drink 2
PNN Poisoned Nothing Nothing N/A 0 N/A
PNP Poisoned Nothing Poison N/A 0 N/A
PPA Poisoned Poison Antidote 3 1 Drink B
PPN Poisoned Poison Nothing N/A 0 N/A
PPP Poisoned Poison Poison N/A 0 N/A

If we ignore all combinations that result in 0 points, there are 13 combinations. Of those 13, four of them are effectively duplicates (such as NAA and NPP), leaving us with a total number of 9 unique combinations.

Four of those nine combinations are won by not drinking anything (those of which the drinker is not poisoned will always be won by not drinking). Four of those nine can be won by drinking Glass A. Four of those nine can be won by drinking Glass B. Three can be won by drinking both glasses.